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CBSE Class 12 Physics 2023 Outside Delhi Set 2 Paper

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Question : 4 of 13
Marks: +1, -0
A steady current of 8 mA8\,\mathrm{mA} flows through a wire. The number of electrons passing through a cross-section of the wire in 10 s10\,\mathrm{s} is
Solution:     👈: Video Solution
    n=  Ite\;\; n = \; \frac{I t}{e}
  Or,    n=  8×10−3×101.6×10−19\; \text{Or,} \;\; n = \; \frac{8 \times 10^{-3} \times 10}{1.6 \times 10^{-19}}
∴  n=5×1017\therefore \; n = 5 \times 10^{17}
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