CBSE Class 12 Chemistry 2013 Solved Paper

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Question : 20
Total: 30
Determine the osmotic pressure of a solution prepared by dissolving 2.5×10−2g of K2SO4 in 2L of water at 25°C, assuming that it is completely dissociated.
(R=0.0821L1atmK‌−1mol−1., Molar mass of K2SO4 =174gmol−1)
Solution:  
Reaction is:
K2SO4→2K++SO42−
No. of produced ions =3
Ï€=iCRT
Ï€=
3×0.025×0.0821×0.5×298
174

=
0.917
174

=0.00527
=5.27×10−3atm
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