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CBSE Class 10 Science 2017 Delhi Term II Set 3 Paper

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Question : 7 of 10
Marks: +1, -0
Complete the following chemical equations:
(i) C2H5OH+O2→\mathrm{C}_2\mathrm{H}_5\mathrm{OH}+\mathrm{O}_2 \rightarrow
(ii) C2H5OH  →443 K Conc. H2SO4\mathrm{C}_2\mathrm{H}_5\mathrm{OH} \; \xrightarrow[443\,\mathrm{K}]{\text{ Conc. } \mathrm{H}_2\mathrm{SO}_4}  
Solution:  
(i) C2H5OH+3 O2→Δ2 CO2+3 H2O\mathrm{C}_2\mathrm{H}_5\mathrm{OH} + 3\,\mathrm{O}_2 \xrightarrow{\Delta} 2\,\mathrm{CO}_2 + 3\,\mathrm{H}_2\mathrm{O}+ Energy
(ii) C2H5OH→443 K Conc. H2SO4.CH2=CH2+H2O\mathrm{C}_2\mathrm{H}_5\mathrm{OH} \xrightarrow[443\,\mathrm{K}]{\text{ Conc. } \mathrm{H}_2\mathrm{SO}_4 .} \mathrm{CH}_2=\mathrm{CH}_2 + \mathrm{H}_2\mathrm{O}
(iii) CH3COOH+NaHCO3→CH3COONa+H2O+CO2↑\mathrm{CH}_3\mathrm{COOH} + \mathrm{NaHCO}_3 \rightarrow \mathrm{CH}_3\mathrm{COONa} + \mathrm{H}_2\mathrm{O} + \mathrm{CO}_2 \uparrow
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