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Volumes Practice Test 4

Question : 1 of 16

Marks: +1, -0

Solution:

Concept:

Volume of water flowing through the pipe in

40

minutes equals the volume added to the cuboid tank.

Explanation:

Pipe cross-section area

= 5\,\mathrm{cm} \times 3\,\mathrm{cm} = 0.05\,\mathrm{m} \times 0.03\,\mathrm{m} = 0.0015\,\mathrm{m}^2

Speed of water

= 10\,\mathrm{m/s}

Time

= 40\,\mathrm{min} = 40 \times 60 = 2400\,\mathrm{s}

Volume of water in

40

minutes

= 0.0015 \times 10 \times 2400 = 36\,\mathrm{m}^3

Let the water rise to height

h

in the tank.

Tank base area

= 7.2 \times 2.5 = 18\,\mathrm{m}^2

So,

18 \times h = 36

Thus,

h = \frac{36}{18} = 2\,\mathrm{m}

Answer:

The water level will rise to

\boxed{2\,\mathrm{m}}

, so the correct option is B.

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