∆Tb=iKb×m ∆Tb∝i×m By considering molarity same as molality (1) 0.01MNa2SO4i×m=3×0.01=0.03 (2) 0.015MC6H12O6i×m=1×0.015=0.015 (3) 0.01 M Urea i×m=1×0.01=0.01 (4) 0.01MKNO3i×m=2×0.01=0.02 Tb′=Tb*+∆Tb Higher the value of (i×m) more will be the boiling point.