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MHT CET 2018 Math Solved Paper
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© examsnet.com
Question : 1
Total: 50
If
k
∫
0
d
x
2
+
18
x
2
=
π
24
, then the value of K is
3
4
1
3
1
4
Validate
Solution:
(c) Here,
k
∫
0
d
x
2
+
18
x
2
=
π
24
⇒
π
24
=
1
18
k
∫
0
d
x
(
1
9
)
+
x
2
=
1
18
k
∫
0
d
x
(
1
3
)
2
+
x
2
⇒
π
24
=
1
18
×
1
(
1
3
)
tan
−
1
[
x
(
1
3
)
]
0
k
⇒
π
24
=
3
18
tan
−
1
[
3
x
]
0
k
=
1
6
[
tan
−
1
3
k
−
tan
−
1
0
]
⇒
π
24
=
1
6
[
tan
−
1
3
k
−
0
]
∴
6
π
24
=
tan
−
1
3
k
⇒
tan
π
4
=
3
k
⇒
1
=
3
K
⇒
K
=
1
3
© examsnet.com
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