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KEAM 2010 Physics and Chemistry Solved Papers
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© examsnet.com
Question : 1
Total: 119
Two resistors of resistances
200
k
Ω
and
1
M
Ω
respectively form a potential divider with outer junctions maintained at potentials of
+
3
V
and
−
15
V
. Then, the potential at the junction between the resistors is
+
1
V
−
0.6
V
0
−
12
V
+
12
V
Validate
Solution:
Current
i
=
V
1
−
V
2
R
1
+
R
2
=
18
1.2
×
10
−
6
V across
1
M
Ω
=
18
1.2
×
10
−
6
×
1
×
10
−
6
=
15
V
∴ Potential at
P
=
15
−
15
=
0
© examsnet.com
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