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Test Index
JEE Main Physics Class 11 Physical world and Measurements Part 1 Questions
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© examsnet.com
Question : 1
Total: 100
In a screw gauge, 5th division of the circular scale coincides with the reference line when the ratchet is closed. There are 50 divisions on the circular scale, and the main scale moves by
0.5
mm
on a complete rotation. For a particular observation the reading on the main scale is
5
mm
and the 20th division of the circular scale coincides with reference line. Calculate the true reading.
[26 Aug 2021 Shift 1]
5.00 mm
5.25 mm
5.15 mm
5.20 mm
Validate
Solution:
Least count of a screw gauge is given by
Least count
(
LC
)
=
Pitch
Number
of
circular
scale
divisions
⇒
LC
=
0.5
50
...(i)
The actual reading (true reading)
= Main scale reading + Least count × Circular division − Zero error
=
5
+
(
0.5
50
)
×
20
−
0.5
50
×
5
[∴ Zero error = Least count × Coinciding division]
=
5
+
0.5
50
(
20
−
5
)
=
5
+
0.5
50
(
15
)
=
5
+
15
100
=
515
100
mm
=
5.15
mm
© examsnet.com
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