If f(x)={\\begin{array}{c}x^3 \sin \\ (\\\{1\end\frac{array}{x}) , , x \neq 0 ; 0, , x=0}., then [6 Apr 2024 Shift 1]

Correct Answer is : f′′(2π)=24−π22π

f^{' '} (\frac{2}{\pi}) =\frac{24-\pi^2}{2 \pi}

f^{' '} (\frac{2}{\pi}) =\frac{12-\pi^2}{2 \pi}

Correct Answer is : f′′(2π)=24−π22π

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JEE Main 6 Apr 2024 Shift 1 Solved Paper

Section: Mathematics

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