JEE Main 2017 Solved Paper Solved Paper

Time taken to reach the extreme position from equilibrium position is

T

4

.Velocity is maximum at equilibrium position and zero at extreme position.
V=A‌ω‌cos‌ωt
K.E=

1

2

mv2 (m is the mass of particle and v is the velocity of particle)
K.E. =

1

2

mA2ω2cos2ωt
Hence graph of K.E. v/s time is square cos function