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Alternating Current
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Section:
Physics
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© examsnet.com
Question : 1
Total: 13
A circuit with an electrical load having impedance
Z
is connected with an AC source as shown in the diagram. The source voltage varies in time as
V
(
t
)
=
300
s
i
n
‌
(
400
t
)
V
, where
t
is time in s. List-I shows various options for the load. The possible currents
i
(
t
)
in the circuit as a function of time are given in List-II.
Choose the option that describes the correct match between the entries in List-I to those in List-II.
List-I
List-II
(P)
(1)
(Q)
(2)
(R)
(3)
(S)
(4)
(5)
[JEE Adv 2025 P1]
P
⟶
3
,
Q
⟶
5
,
R
⟶
2
,
S
⟶
1
P
⟶
1
,
Q
⟶
5
,
R
⟶
2
,
S
⟶
3
P
⟶
3
,
Q
⟶
4
,
R
⟶
2
,
S
⟶
1
P
⟶
1
,
Q
⟶
4
,
R
⟶
2
,
S
⟶
5
Validate
Solution:
V
(
t
)
=
300
s
i
n
‌
(
400
t
)
(P)
‌
‌
30S
‌
‌
⇒
‌
‌
i
0
=
‌
300
30
=
10
A
and
φ
=
0
⇒
‌
‌
(
P
)
⟶
(
3
)
(Q)
‌
⇒
‌
‌
Z
=
√
R
2
+
(
ω
L
)
2
‌
‌
‌
=
√
(
30
)
2
+
(
400
×
100
×
10
−
3
)
2
=
50
Ω
‌
∴
‌
‌
i
0
=
‌
300
50
=
6
A
‌
‌
‌
φ
=
tan
−
1
(
‌
ω
L
R
)
=
53
∘
(
lag
)
‌
‌
‌
(
Q
)
⟶
(
5
)
(R)
Z
=
√
(
30
)
2
+
(
‌
1
400
×
50
×
10
−
6
−
400
×
25
×
10
−
3
)
2
=
√
(
30
)
2
+
(
40
)
2
=
50
Ω
∴
‌
‌
R
⟶
(
2
)
(S)
Z
=
√
(
60
)
2
+
(
‌
1
50
×
10
−
6
×
400
−
125
×
10
−
3
×
400
)
=
√
(
60
)
2
+
(
50
−
50
)
2
=
60
Ω
∴
‌
‌
i
0
=
‌
300
60
=
5
A
‌
(
S
)
⟶
1
© examsnet.com
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