Test Index

JEE Advanced 2020 Concept Recapitulation Test 4 Paper 2

© examsnet.com

Question : 1

Total: 54

If a narrow beam of light falls on a glass hemisphere of refraction index 2 as shown in the figure. Then the image formed.

Due to first surface has co-ordinates (−√2R,−√2R)
Due to first surface has co-ordinates (−√3R,−√3R)
Due to second surface has co-ordinates (−R∕√2,R∕√2)
Due to second surface has co-ordinates (−R∕√3,R∕√3)

Go to Question:

Next Question