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IIT JEE Advanced 2006 Question Paper 1
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© examsnet.com
Question : 1
Total: 120
In the following circuits, it is given that
R
1
= 1 Ω,
R
2
= 2 Ω,
C
1
= 2 μF and
C
2
= 4 μF.
The time constants (in μs) for the circuits I, II, III are, respectively,
18, 8/9, 4
18, 4, 8/9
4, 8/9, 18
8/9, 18, 4
Validate
Solution:
Circuit (I): We have
τ
1
=
C
1
C
2
C
1
+
C
2
×
R
1
×
R
2
R
1
+
R
2
=
8
6
×
2
3
=
8
9
µs
Circuit (II): We have
τ
2
=
(
C
1
+
C
2
)
(
R
1
+
R
2
)
= 18 μs
Circuit (III): We have
τ
3
=
(
C
1
+
C
1
)
(
R
1
R
2
R
1
+
R
2
)
= 4µs
© examsnet.com
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