Say you have an equation. (x-1)(x-2)(x-3)=0 ⇒(x2−3x+2)(x−3)=0 ⇒x3−6x2+11x−6=0 By the question, x=3,an=−6,a1=−6 Substitute the above values in the option. Option (a): (−6)3≥33×−6 ⇒ -216≥−168 This is incorrect, thus option (a) is incorrect. Option (b): 33≥(−6)3×−6 27≥64 Option (c): (−6)3=33×−6 ⇒ −216≥−168 This is incorrect, thus option (c) is incorrect. Thus, none of the options is necessarily true.