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Redox Reactions

Section: Chemistry

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Question : 1 of 13

Marks: +1, -0

\mathrm{H}_2\mathrm{O}_2

\mathrm{KMnO}_4

in acidic medium to '

x

' and in basic medium to '

y

x

y

[AP EAPCET 23 May 2025 S2]

$\;x= \mathrm{MnO}_2, y= \mathrm{Mn}^{2+}$
$\;x= \mathrm{Mn}^{2+}, y= \mathrm{MnO}_2$
$\;x= \mathrm{MnO}_4^{2-}, y= \mathrm{Mn}^{2+}$
$\;x= \mathrm{MnO}_2, y= \mathrm{MnO}_4^{2-}$

Solution:

In acidic condition,

\mathrm{KMnO}_4( \mathrm{Mn}=+7

oxidation state

)

reduced by

\mathrm{H}_2\mathrm{O}_2

to

\mathrm{Mn}^{2+}

So,

x=\mathrm{Mn}^{2+}

In basic condition

\mathrm{KMnO}_4( \mathrm{Mn}=+7

oxidation state

)

is reduced by

\mathrm{H}_2\mathrm{O}_2

to

\mathrm{MnO}_2 y= \mathrm{MnO}_2

Acidic

2\mathrm{KMnO}_4+5\mathrm{H}_2\mathrm{O}_2+3\mathrm{H}_2\mathrm{SO}_4 ightarrow 2\mathrm{MnSO}_4+\mathrm{K}_2\mathrm{SO}_4+8\mathrm{H}_2\mathrm{O}+5\mathrm{O}_2

Basic

2\mathrm{KMnO}_4+3\mathrm{H}_2\mathrm{O} \longrightarrow 2\mathrm{MnO}_2+2\mathrm{KOH}+2\mathrm{H}_2\mathrm{O}+3\mathrm{O}_2

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