Convert the percentage ionisation to decimalαA​=1004.242​=0.04242α=CKα​​​⇒CA​=αA2​Kα​​CA​=(0.042422.1.8×10−5​,CA​=0.01MαB​=1003​=0.03CB​=αB2​Kα​​=(0.03)21.8×10−5​=0.02MMoles from solution A,nA​=CA​×VA​=0.01M×1L=0.01molnB​=cB​×VB​=0.02M×1L=0.02molnTotal​=nA​+nB​=0.03molVTotal​=VA​+VB​=1+1=2LcFinal​=VTotal​nTotal​​=2L0.03​=0.015M