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NCERT Class XII Mathematics Chapter - - Solutions

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Exercise - 7.3
Find the integrals of the functions in Exercises 62 to 83.
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Question : 79 of 271
Marks: +1, -0
cos⁡2x+2sin⁡2xcos⁡2x\frac{\cos 2x+2\sin^2 x}{\cos^2 x}
Solution:  
Let I=∫cos⁡2x+2sin⁡2xcos⁡2xdxI=\int\frac{\cos 2x+2\sin^2 x}{\cos^2 x}dx
=∫(cos⁡2x−sin⁡2x)+2sin⁡2xcos⁡2xdx=\int\frac{(\cos^2 x-\sin^2 x)+2\sin^2 x}{\cos^2 x}dx
=∫cos⁡2x+sin⁡2xcos⁡2xdx=\int\frac{\cos^2 x+\sin^2 x}{\cos^2 x}dx
=∫1cos⁡2xdx=\int\frac{1}{\cos^2 x}dx
=∫sec⁡2x dx=tan⁡x+C=\int\sec^2 x\,dx=\tan x+C
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