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NCERT Class XII Mathematics Chapter - - Solutions

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Question : 65 of 78
Marks: +1, -0
If the line x−1−3=y−22k=z−32\frac{x-1}{-3}=\frac{y-2}{2k}=\frac{z-3}{2} and x−13k=y−11=z−6−5\frac{x-1}{3k}=\frac{y-1}{1}=\frac{z-6}{-5} are perpendicular, find the value of k.
Solution:  
The given lines are x−1−3=y−22k=z−32\frac{x-1}{-3}=\frac{y-2}{2k}=\frac{z-3}{2}...(1)
and x−13k=y−11=z−6−5\frac{x-1}{3k}=\frac{y-1}{1}=\frac{z-6}{-5} ...(2)
The direction ratios of line (1) are < –3, 2k, 2 >
The direction ratios of line (2) are < 3k, 1, –5 >
The line (1) and (2) are perpendicular
if (–3) (3k) + (2k) (1) + (2) (–5) = 0
if – 9k + 2k – 10 = 0 if 7k = –10 if k=−107k = -\frac{10}{7}
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