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NCERT Class XII Mathematics Chapter - - Solutions

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Exercise - 7.2
Integrate the functions in Exercises 23 to 59.
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Question : 53 of 271
Marks: +1, -0
sin⁡x(1+cos⁡x)2\frac{\sin x}{(1+\cos x)^2}
Solution:  
Let I=sin⁡x(1+cos⁡x)2dxI = \frac{\sin x}{(1+\cos x)^2} dx
Put 1+cos⁡x=t1 + \cos x = t ⇒−sin⁡x dx=dt\Rightarrow - \sin x \, dx = dt
∴I=−∫dtt2=t−2+1−2+1+C\therefore I = -\int \frac{dt}{t^2} = \frac{t^{-2+1}}{-2+1} + C =1t+C= \frac{1}{t} + C =11+cos⁡x+C= \frac{1}{1+\cos x} + C
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