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NCERT Class XII Mathematics Chapter - - Solutions

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Exercise - 7.2
Integrate the functions in Exercises 23 to 59.
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Question : 40 of 271
Marks: +1, -0
etan⁡−1x1+x2\frac{e^{\tan^{-1}x}}{1+x^2}
Solution:  
Let I=∫etan⁡−1x1+x2dxI = \int \frac{e^{\tan^{-1}x}}{1+x^2}dx
Put tan⁡−1x=t\tan^{-1}x = t ⇒11+x2dx=dt\Rightarrow \frac{1}{1+x^2}dx = dt
∴I=∫etdt=et+C\therefore I = \int e^t dt = e^t + C =etan⁡−1x+C= e^{\tan^{-1}x} + C
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