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NCERT Class XII Mathematics Chapter - - Solutions

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Exercise - 7.2
Integrate the functions in Exercises 23 to 59.
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Question : 37 of 271
Marks: +1, -0
x9−4x2\frac{x}{9-4x^2}
Solution:  
Let I=∫x9−4x2dxI = \int \frac{x}{9-4x^2} dx
Put 9−4x2=t9 - 4x^{2} = t ⇒−8xdx=dt\Rightarrow -8x dx = dt
∴I=−18∫dtt=−18log⁡∣t∣+C\therefore I = -\frac{1}{8} \int \frac{dt}{t} = -\frac{1}{8} \log|t| + C =18log⁡1∣t∣+C= \frac{1}{8} \log \frac{1}{|t|} + C =18log⁡1∣9−4x2∣+C= \frac{1}{8} \log \frac{1}{|9-4x^{2}|} + C
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