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NCERT Class XII Mathematics Chapter - - Solutions

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Exercise - 7.2
Integrate the functions in Exercises 23 to 59.
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Question : 29 of 271
Marks: +1, -0
xx+2x\sqrt{x+2}
Solution:  
Let I=∫xx+2I=\int x\sqrt{x+2}
Put x+2=tx + 2 = t ⇒dx=dt\Rightarrow dx = dt. Also x=t−2x = t - 2
∴I=∫(t−2)tdt\therefore I=\int (t-2)\sqrt{t}dt =∫(t3/2−2t1/2)dt=\int (t^{3/2}-2t^{1/2})dt
=25t5/2−2×23t3/2+C=\frac{2}{5}t^{5/2}-2\times\frac{2}{3}t^{3/2}+C
=25(x+2)5/2−43(x+2)3/2+C=\frac{2}{5}(x+2)^{5/2}-\frac{4}{3}(x+2)^{3/2}+C
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