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NCERT Class XII Mathematics Chapter - - Solutions

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..... Miscellaneous Exercise .....
Integrate the functions in Exercises 229 to 252.
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Question : 237 of 271
Marks: +1, -0
cos⁡x4−sin⁡2x\frac{\cos x}{\sqrt{4-\sin^2 x}}
Solution:  
Let I=∫cos⁡x4−sin⁡2xdxI=\int \frac{\cos x}{\sqrt{4-\sin^2 x}}dx
Let sin⁡x=t\sin x = t ⇒cos⁡xdx=dt\Rightarrow \cos x dx = dt
∴I=∫dt4−t2\therefore I=\int\frac{dt}{\sqrt{4-t^2}} =sin⁡−1(t2)+C=\sin^{-1}\left(\frac{t}{2}\right)+C =sin⁡−1(sin⁡x2)+C=\sin^{-1}\left(\frac{\sin x}{2}\right)+C
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