Test Index

NCERT Class XII Mathematics Chapter - - Solutions

Show Para  Hide Para 
..... Miscellaneous Exercise .....
Integrate the functions in Exercises 229 to 252.
© examsnet.com
Question : 230 of 271
Marks: +1, -0
1x+a+x+b\frac{1}{\sqrt{x+a}+\sqrt{x+b}}
Solution:  
Let I=∫1x+a+x+b dxI = \int \frac{1}{\sqrt{x+a}+\sqrt{x+b}} \, dx
=∫1x+a+x+b×x+a−x+bx+a−x+b dx= \int \frac{1}{\sqrt{x+a}+\sqrt{x+b}} \times \frac{\sqrt{x+a}-\sqrt{x+b}}{\sqrt{x+a}-\sqrt{x+b}} \, dx
=∫x+a−x+b(x+a)2−(x+b)2 dx= \int \frac{\sqrt{x+a}-\sqrt{x+b}}{(\sqrt{x+a})^2 - (\sqrt{x+b})^2} \, dx
=1a−b∫[(x+a)1/2−(x+b)1/2]dx= \frac{1}{a-b} \int \left[ (x+a)^{1/2} - (x+b)^{1/2} \right] dx
=1a−b[(x+a)3/232⋅1−(x+b)3/232⋅1]+C= \frac{1}{a-b} \left[ \frac{(x+a)^{3/2}}{\frac{3}{2} \cdot 1} - \frac{(x+b)^{3/2}}{\frac{3}{2} \cdot 1} \right] + C
=23(a−b)[(x+a)3/2−(x+b)3/2]+C= \frac{2}{3(a-b)} \left[ (x+a)^{3/2} - (x+b)^{3/2} \right] + C
© examsnet.com
Go to Question:
Advertisements