Test Index

NCERT Class XII Mathematics Chapter - - Solutions

Show Para  Hide Para 
Exercise - 7.11
By using the properties of definite integrals, evaluate the integrals in Exercises 208 to 225.
© examsnet.com
Question : 214 of 271
Marks: +1, -0
∫0π/4log⁡(1+tan⁡x)dx\int\limits_{0}^{\pi/4}\log(1+\tan x)dx
Solution:  
Let I=∫0π/4log⁡(1+tan⁡x)dxI=\int\limits_{0}^{\pi/4}\log(1+\tan x)dx ...(i)
Also, ∫0π/4log⁡[1+tan⁡(π/4−x)]dx\int\limits_{0}^{\pi/4}\log[1+\tan(\pi/4-x)]dx [∵∫0af(x)dx=∫0af(a−x)dx]\left[\because \int\limits_{0}^{a}f(x)dx=\int\limits_{0}^{a}f(a-x)dx\right]
I=∫0π/4log⁡(1+1−tan⁡x1+tan⁡x)dxI=\int\limits_{0}^{\pi/4}\log\left(1+\frac{1-\tan x}{1+\tan x}\right)dx
=∫0π/4log⁡(21+tan⁡x)dx=\int\limits_{0}^{\pi/4}\log\left(\frac{2}{1+\tan x}\right)dx
=∫0π/4log⁡2 dx−∫0π/4log⁡(1+tan⁡x)dx=\int\limits_{0}^{\pi/4}\log2\,dx-\int\limits_{0}^{\pi/4}\log(1+\tan x)dx
=log⁡2∫0π/41 dx−I=\log 2\int\limits_{0}^{\pi/4}1\,dx-I
2I=[log⁡x]0π/4=(log⁡2)(π/4−0)2I=\left[\log x\right]_{0}^{\pi/4}=(\log 2)(\pi/4-0)
⇒I=π8log⁡2\Rightarrow I=\frac{\pi}{8}\log 2
© examsnet.com
Go to Question:
Advertisements