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NCERT Class XII Mathematics Chapter - - Solutions

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Exercise - 7.9
Evaluate the definite integrals in Exercises 176 to 195.
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Question : 192 of 271
Marks: +1, -0
∫0π4(2sec⁡2x+x3+2)dx\int\limits_{0}^{\frac{\pi}{4}}(2\sec^2 x+x^3+2)dx
Solution:  
Let I=∫0π4(2sec⁡2x+x3+2)dxI=\int\limits_{0}^{\frac{\pi}{4}}(2\sec^2 x+x^3+2)dx
=[2tan⁡x+x44+2x]0π4=\left[2\tan x+\frac{x^4}{4}+2x\right]_{0}^{\frac{\pi}{4}}
=2(tan⁡π4−tan⁡0)+14(π4256−0)+2(π4−0)=2\left(\tan\frac{\pi}{4}-\tan 0\right)+\frac{1}{4}\left(\frac{\pi^4}{256}-0\right)+2\left(\frac{\pi}{4}-0\right)
=2(1−0)+π41024+π2=2(1-0)+\frac{\pi^4}{1024}+\frac{\pi}{2}
=π41024+π2+2=\frac{\pi^4}{1024}+\frac{\pi}{2}+2
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