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NCERT Class XII Mathematics Chapter - - Solutions

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Exercise - 7.9
Evaluate the definite integrals in Exercises 176 to 195.
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Question : 185 of 271
Marks: +1, -0
∫01dx1+x2\int\limits_{0}^{1} \frac{dx}{1+x^2}
Solution:  
∫01dx1+x2\int\limits_{0}^{1} \frac{dx}{1+x^2}
=[an−1x]01=[ an^{-1}x]^1_0
=an−1(1)−an−1(0)= an^{-1}(1)- an^{-1}(0) =π4=\frac{\pi}{4}
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