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NCERT Class XII Mathematics Chapter - - Solutions

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Question : 17 of 78
Marks: +1, -0
Find the angle between the following pair of lines:x22=y15=z+33\frac{x-2}{2} = \frac{y-1}{5} = \frac{z+3}{-3} and x+21=y48=z54\frac{x+2}{-1} = \frac{y-4}{8} = \frac{z-5}{4}
Solution:  
Direction ratios of the given lines are respectively< 2, 5, –3> and < –1, 8, 4>
Let θ be the angle between the given lines, then
cosθ=a1a2+b1b2+c1c2a12+b12+c12a22+b22+c22,\cos \theta = \left| \frac{a_1 a_2 + b_1 b_2 + c_1 c_2}{\sqrt{a_1^2 + b_1^2 + c_1^2} \sqrt{a_2^2 + b_2^2 + c_2^2}} \right|,
where a1,b1,c1a_1, b_1, c_1 and a2,b2,c2a_2, b_2, c_2 are direction ratios
cosθ\cos \theta =2×(1)+5×8+(3)×422+52+(3)2(1)2+82+42= \frac{\left| 2 \times (-1) + 5 \times 8 + (-3) \times 4 \right|}{\sqrt{2^2 + 5^2 + (-3)^2} \sqrt{(-1)^2 + 8^2 + 4^2}}
=263881=26938= \frac{26}{\sqrt{38} \sqrt{81}} = \frac{26}{9 \sqrt{38}}
θ=cos126938\Rightarrow \theta = \cos^{-1} \frac{26}{9 \sqrt{38}}
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