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NCERT Class XII Mathematics Chapter - - Solutions

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Choose the correct answer in Exercises 167 to 168.
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Question : 169 of 271
Marks: +1, -0
∫x2−8x+7 dx\int\sqrt{x^2-8x+7}\,dx is equal to
Solution:  
I=∫x2−8x+7 dxI=\int\sqrt{x^2-8x+7}\,dx =∫(x−4)2−32 dx=\int\sqrt{(x-4)^2-3^2}\,dx
=12(x−4)x2−8x+7−92log⁡∣x−4+x2−8x+7∣+C=\frac{1}{2}(x-4)\sqrt{x^2-8x+7}-\frac{9}{2}\log |x-4+\sqrt{x^2-8x+7}|+C
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