Test Index

NCERT Class XII Mathematics Chapter - - Solutions

Show Para  Hide Para 
Exercise - 7.7
Integrate the functions in Exercises 158 to 166.
© examsnet.com
Question : 164 of 271
Marks: +1, -0
1+3x−x2\sqrt{1+3x-x^2}
Solution:  
Let I=∫1+3x−x2dxI=\int \sqrt{1+3x-x^2} dx
=∫1−(x2−3x)dx=\int \sqrt{1-(x^2-3x)} dx
=∫1−(x2−3x+94)+94dx=\int \sqrt{1-\left(x^2-3x+\frac{9}{4}\right)+\frac{9}{4}} dx
=∫(132)2−(x−32)2dx=\int \sqrt{\left(\frac{\sqrt{13}}{2}\right)^2 - \left(x-\frac{3}{2}\right)^2} dx
=[x−322⋅134−(x−32)2+138sin⁡−1(x−32132)]+C=\left[ \frac{x-\frac{3}{2}}{2} \cdot \sqrt{\frac{13}{4} - \left(x-\frac{3}{2}\right)^2} + \frac{13}{8} \sin^{-1}\left(\frac{x-\frac{3}{2}}{\frac{\sqrt{13}}{2}}\right) \right] + C
=2x−341+3x−x2+138sin⁡−1(2x−313)+C=\frac{2x-3}{4} \sqrt{1+3x-x^2} + \frac{13}{8} \sin^{-1}\left(\frac{2x-3}{\sqrt{13}}\right) + C
© examsnet.com
Go to Question:
Advertisements