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NCERT Class XII Mathematics Chapter - - Solutions

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Exercise - 7.6
Integrate the functions in Exercises 134 to 155.
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Question : 153 of 271
Marks: +1, -0
(x−3)ex(x−1)3\frac{(x-3)e^x}{(x-1)^3}
Solution:  
Let I=∫(x−3)ex(x−1)3dxI = \int\frac{(x-3)e^x}{(x-1)^3}dx
=∫ex((x−1)−2)(x−1)3dx= \int\frac{e^x((x-1)-2)}{(x-1)^3}dx
=∫ex[1(x−1)2−2(x−1)3]dx= \int e^x\left[\frac{1}{(x-1)^2} - \frac{2}{(x-1)^3}\right]dx
=∫ex[1(x−1)2+ddx(1(x−1)2)]dx= \int e^x\left[\frac{1}{(x-1)^2} + \frac{d}{dx}\left(\frac{1}{(x-1)^2}\right)\right]dx
=ex(x−1)2+C= \frac{e^x}{(x-1)^2} + C [∵∫ex(f(x)+f′(x))dx=exf(x)+C]\left[\because \int e^x(f(x)+f'(x))dx = e^x f(x) + C\right]
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