As the required line is parallel to the line $\frac{x+3}{3} = \frac{y-4}{5} = \frac{z+8}{6}$ therefore, the line has direction ratios < 3, 5, 6 >.Also, the line passes through (–2, 4, –5). Therefore, the equation of the line in (cartesian form) is $\frac{x-(-2)}{3} = \frac{y-4}{5} = \frac{z-(-5)}{6}$$\Rightarrow \frac{x+2}{3} = \frac{y-4}{5} = \frac{z+5}{6}$