Test Index

NCERT Class XII Chemistry
Chapter - The p-Block Elements
Questions with Solutions

© examsnet.com
Question : 33 of 74
Marks: +1, -0
How are xenon fluorides XeF2,XeF4\mathrm{XeF}_2, \mathrm{XeF}_4and XeF6\mathrm{XeF}_6 obtained?
Solution:  
Xenon forms three binary fluorides, XeF2,XeF4\mathrm{XeF}_2, \mathrm{XeF}_4 and XeF6\mathrm{XeF}_6 by thedirect reaction of elements under appropriate experimental conditions.
Xe(g)+F2(g)→1 bar673 KXeF2(s)\mathrm{Xe}_{(g)} + \mathrm{F}_{2(g)} \xrightarrow[1\,\mathrm{bar}]{673\,\mathrm{K}} \mathrm{XeF}_{2(s)}
xenon in excess\text{xenon in excess}
Xe(g)+2 F2(g)→7 bar873 KXeF4(s)\mathrm{Xe}_{(g)} + 2\,\mathrm{F}_{2(g)} \xrightarrow[7\,\mathrm{bar}]{873\,\mathrm{K}} \mathrm{XeF}_{4(s)}
1 : 5 ratio\text{1 : 5 ratio}
Xe(g)+3 F2(g)→60−70 bar573 KXeF6(s)\mathrm{Xe}_{(g)} + 3\,\mathrm{F}_{2(g)} \xrightarrow[60-70\,\mathrm{bar}]{573\,\mathrm{K}} \mathrm{XeF}_{6(s)}
1 : 20 ratio\text{1 : 20 ratio}
© examsnet.com
Go to Question:
Prev Question
Next Question