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NCERT Class XII Chemistry
Chapter - The p-Block Elements
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Question : 3 of 74
Marks: +1, -0
Discuss the trends in chemical reactivity of group 15 elements.
Solution:  
Nitrogen has very low reactivity due to unavailability of vacantd-orbital and high bond dissociation energy of N ≡≡ N bond.
(a) Hydrides : General formula for hydrides is MH3,e.g.,NH3,PH3,MH_3, e.g., NH_3, PH_3, AsH3,SbH3,BiH3AsH_3,SbH_3, BiH_3. All these hydridesarecovalent in nature and have pyramidalstructure (sp3sp^{3}hybridized).
 Property  Down thegroup  Reason
 Basicstrength 3^{3}  decreases  The size of central atom increases, electrondensity decreases.
 Thermalstability of MH3^{3}  decreases  The size of the central atom increases,its tendency to form stable M – H bondsdecreases.
 Reducingcharacter  increases  The stability of hydrides decreases, thus thereducing character increases.
 Melting andboiling point  increases(except in N)  NH3NH_3 has high melting point and boilingpoint than PH3PH_3 due to hydrogen bonding.As the molecular size increases van derWaals forces increases.
(b) Halides : Elements of group 15 form two types of halides vizviz. trihalidesand pentahalides. The halides are predominantly basic (Lewis bases) innature and have lone pair of electrons (central atom is sp3sp^{3}hybridized).The pentahalides arethermallyless stable than the trihalides.
 Property  Gradation  Reason
 Stability of trihalidesof nitrogen  NF3>NCl3>NBr3NF_3 > NCl_3> NBr_3  Large size difference between Nand the halogens
 Lewis base strength  NF3< NCl3{NF}_{3} < \ {NCl}_{3}< NBr3< NI3< \ {NBr}_{3} < \ {NI}_{3}  Decreasing electronegativity ofhalogens
 Bond angle amongthe halides ofphosphorus  Â PF3< PCl3<\ {PF}_{3} < \ {PCl}_{3}< PBr3< PI3\ {PBr}_{3} < \ {PI}_{3}  Due to decreased bond pair-bondpair repulsion
(c) Oxides : All the elements of this group form two types of oxidesi.e.,M2O3i.e.,M_2O_3 and M2O5M_2O_5 and are called trioxides and pentoxides.
 Property  Gradation  Reason
 Acidic strengthof trioxides  Â N2O3>P2O3>\ {N}_{2} {O}_{3}> {P}_{2} {O}_{3}> As2O3\ {As}_{2} {O}_{3}  Electronegativity of central atomdecreases
 Acidic strengthof pentoxide  N2O5> P2O5>{N}_{2} {O}_{5}>\ {P}_{2} {O}_{5}> As2O5> Sb2O5>\ {As}_{2} {O}_{5}>\ {Sb}_{2} {O}_{5}> Bi2O5\ {Bi}_{2} {O}_{5}  Electronegativity of central atomdecreases.
 Acidic strengthof oxides ofnitrogen  Â N2O< NO< N2O3\ {N}_{2} {O} < \ {NO} < \ {N}_{2} {O}_{3}<N2O4<N2O5< {N}_{2} {O}_{4}< {N}_{2} {O}_{5}  Oxidation state of central atomincreases
 Stability ofpentoxide  Â P2O5> As2O5>\ {P}_{2} {O}_{5}>\ {As}_{2} {O}_{5}> Sb2O5> N2O5>\ {Sb}_{2} {O}_{5}>\ {N}_{2} {O}_{5}> Bi2O5\ {Bi}_{2} {O}_{5}  Stability of oxides of a higheroxidation state i.e.,M2O5i.e., M_2O_5 decreaseswith increasing atomic number
(d) Oxoacids : The elements of this group form a number of oxoacids out of which those of N and P are more common.
Oxoacids of N :
 Formula (Name)  Ox. state of N
 H2N2O2H_2N_2O_2 (Hyponitrous acid)  +1
 HNO2HNO_2 (Nitrous acid)  +3
 HNO3HNO_3 (Nitric acid)  +5
 Formula (Name)  Ox. state  Basicity
 H3PO3H_3PO_3 (Phosphorous acid)  +3  2
 H3PO4H_3PO_4 (Orthophosphoric acid)  +5  3
 HPO3HPO_3 (Metaphosphoric acid)  +5  1
 H4P2O6H_4P_2O_6 (Hypophosphoric acid)  +4  4
 H2P2O7H_2P_2O_7 (Pyrophosphoric acid)  +5  4
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