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NCERT Class XII Chemistry
Chapter - The p-Block Elements
Questions with Solutions

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Question : 19 of 74
Marks: +1, -0
Knowing the electron gain enthalpy values for O → O– and O →O2–^{2–} as –141 and 702 kJ mol–1^{–1} respectively, how can you account for the formation of large number of oxides having O2–^{2–} species and not O–^{–} ?
Hint : Consider lattice energy factor in the formation of compound.
Solution:  
This can be explained with the help of electronic configuration.
As O2–^{2–} has most stable configuration amongst these. So, formation of O2–^{2–} ismuch more easier. In solid state, large amount of energy (lattice enthalpy)is released to form divalent O2–^{2–} ions.It is greater lattice enthalpy of O2–^{2–}which compensates for the high energy required to remove the secondelectron.
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