(i) $3d^{3}$: Stable oxidation state will be +5 due to outer electronicconfiguration $3d^{3}4s^{2}$(+2, +3, +4, +5).(ii) $3d^{5}$: Stable oxidation state will be +2 and +7 due to outer electronicconfiguration $3d^{5}4s^{2}$(+2, +3, +4, +6, +7).(iii) $3d^{8}$: Stable oxidation state will be +2 due to outer electronicconfiguration $3d^{8}4s^{2}$(+2, +3, +4).(iv) $3d^{4}$: Stable oxidation state will be +3 and +6 due to outer electronicconfiguration $3d^{4}4s^{2}$. There is no $d^{4}$ configuration in ground state, as itbecomes $3d^{5}4s^{1}$