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NCERT Class XII Chemistry
Chapter - Electrochemistry
Questions with Solutions

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Question : 26 of 32
Marks: +1, -0
Suggest a way to determine the Λ0m\Lambda^{0}m value of water.
Solution:  
Water is a weak electrolyte. Its Λ0m\Lambda^{0m} value can be determined with thehelp of Kohlrausch’s law.
Λm0(HCl)=Λm0(H+)+Λm0(Cl−)\Lambda_{m}^{0}(\mathrm{HCl}) = \Lambda_{m}^{0}(\mathrm{H}^{+}) + \Lambda_{m}^{0}(\mathrm{Cl}^{-}).......(i)
Λm0(NaOH)=Λm0(Na+)+Λm0(OH−)\Lambda_{m}^{0}(\mathrm{NaOH}) = \Lambda_{m}^{0}(\mathrm{Na}^{+}) + \Lambda_{m}^{0}(\mathrm{OH}^{-})........ (ii)
Λm0(NaCl)=Λm0(Na+)+Λm0(Cl−)\Lambda_{m}^{0}(\mathrm{NaCl}) = \Lambda_{m}^{0}(\mathrm{Na}^{+}) + \Lambda_{m}^{0}(\mathrm{Cl}^{-}).......(iii)
Adding (i) and (ii) and subtracting (iii) we get
Λm0(H2O)=Λm0(H+)+Λm0(OH−)\Lambda_{m}^{0}(\mathrm{H}_{2}\mathrm{O}) = \Lambda_{m}^{0}(\mathrm{H}^{+}) + \Lambda_{m}^{0}(\mathrm{OH}^{-})
=Λm0(HCl)+Λm0(NaOH)−Λm0(NaCl)= \Lambda_{m}^{0}(\mathrm{HCl}) + \Lambda_{m}^{0}(\mathrm{NaOH}) - \Lambda_{m}^{0}(\mathrm{NaCl})
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