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NCERT Class XII Chemistry
Chapter - Electrochemistry
Questions with Solutions

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Question : 22 of 32
Marks: +1, -0
Calculate the potential of hydrogen electrode in contact with a solution whose pH is 10.
Solution:  
For hydrogen electrode, H++e−→12H2\mathrm{H}^{+} + \mathrm{e}^{-} \rightarrow \frac{1}{2}\mathrm{H}_2
From Nernst equation,
EH+/H2=EH+/H2∘−0.0591nlog⁡1[H+]E_{\mathrm{H}^{+}/\mathrm{H}_2}=E^{\circ}_{\mathrm{H}^{+}/\mathrm{H}_2} - \frac{0.0591}{n} \log \frac{1}{[\mathrm{H}^+]}
=0−0.05911log⁡110−10=0 - \frac{0.0591}{1} \log \frac{1}{10^{-10}}
=−0.0591imes10=−0.591V= -0.0591 imes 10 = -0.591 \mathrm{V}
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