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NCERT Class XII Chemistry
Chapter - Coordination Compounds
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Question : 15 of 43
Marks: +1, -0
Discuss the nature of bonding in the following coordination entities on the basis of valence bond theory :
(i) [Fe(CN)6]4–[Fe(CN)_6] ^{4–}
(ii) [FeF6]3–[FeF_6] ^{3– }
(iii) [Co(C2O4)3]3–[Co(C_2O_4)_3] ^{3–}
(iv) [CoF6]3−[CoF_6]^{3-}
Solution:  
(i) [Fe(CN)6]4–[Fe(CN)_6] ^{4–}: Fe(26) has electronic configuration [Ar]4s23d6[Ar] 4s^{2} 3d^{6} .
Fe 2+^{2+ } has electronic configuration[Ar]4s23d6[Ar] 4s^{2} 3d^{6}
CN –^{–} ion causes pairing of electrons because it is a strong field ligand.
It has octahedral shape and is diamagnetic in nature due to absence of electrons.
(ii) [FeF6]3–[FeF_6] ^{3– }: Fe(26) has electronic configuration [Ar]4s23d6.Fe3+:[Ar]4s03d5F[Ar] 4s^{2} 3d^{6} . Fe^{3+} : [Ar] 4s^{0} 3d^{5} F being a weak field ligand, does not cause pairing of electrons.
(iii) [Co(C2O4)3]3–[Co(C_2O_4)_3] ^{3–} : Co(27) has electronic configuration [Ar]4s23d7[Ar] 4s^{2} 3d^{7} .
Co3+:[Ar]4s03d6Co^{3+} : [Ar]4s^{0} 3d^{6}
C2O42–C_2O_4 ^{2–} being a strong field ligand causes pairing of electrons.
(iv) [CoF6]3−[CoF_6]^{3-}: Co(27) has electronic configuration [Ar]4s23d7[Ar] 4s^{2} 3d^{7} .
Co3+:[Ar]4s03d6.Co^{3+} : [Ar]4s^{0} 3d^{6} .
F–F– being a weak field ligand, cannot cause pairing of electrons.
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