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NCERT Class XII Chemistry
Chapter - Chemical Kinetics
Questions with Solutions

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Question : 34 of 39
Marks: +1, -0
The conversion of molecules X to Y follows second order kinetics. If concentration of X is increased to three times how will it affect the rate of formation of Y?
Solution:  
The reaction, X → Y, follows second order kinetics hence the rate law equation will be
            \;\;\;\;\;\;Rate =kC2,=k C^{2}, where C=[X]C=[X]
If concentration of X increases three times, now, [X]=3C molL−1[X]=3 C \ \mathrm{mol} \mathrm{L}^{-1}
∴  \therefore\; Rate =k(3C)2=9kC2=k(3 C)^{2}=9 k C^{2}
Thus the rate of reaction will become 9 times. Hence, the rate of formationof Y will increase 9 times.
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