Test Index

NCERT Class XII Chemistry
Chapter - Chemical Kinetics
Questions with Solutions

© examsnet.com
Question : 32 of 39
Marks: +1, -0
In a reaction, 2A → products, the concentration of A decreases from 0.5 mol L−1^{-1} to 0.4 mol L−1^{-1} in 10 minutes. Calculate the rate during this interval.
Solution:  
Average rate =−12Δ[R]Δt=-\frac{1}{2}\frac{\Delta[R]}{\Delta t}
=−12[R]2−[R]1t2−t1=-\frac{1}{2}\frac{[R]_2-[R]_1}{t_2-t_1}
=−12×0.4−0.510=-\frac{1}{2}\times\frac{0.4-0.5}{10}
=−12×−0.1 M10=-\frac{1}{2}\times\frac{-0.1\,\mathrm{M}}{10}
=5×10−3 M min−1=5\times10^{-3}\,\mathrm{M}\,\mathrm{min}^{-1}
© examsnet.com
Go to Question:
Prev Question
Next Question