The decomposition of a hydrocarbon follows ...

NCERT Class XII Chemistry
Chapter - Chemical Kinetics
Questions with Solutions

Question : 26 of 39

Marks: +1, -0

The decomposition of a hydrocarbon follows the equation

k = (4.5 \times 10^{11} \mathrm{s}^{-1}) e^{-\frac{28000 k}{T}}

Calculate

E_{a}.

Solution:

Arrhenius equation,

k = A e^{-\frac{E_d}{RT}}

Given equation is

k = (4.5 \times 10^{11} \mathrm{s}^{-1}) e^{-\frac{2800 K}{T}}

Comparing both the equations, we get

\frac{E_a}{RT} = -\frac{28000 K}{T}

or,

E_a = 28000 K \times R

= 28000 \times 8.314

= 232.79 \mathrm{kJ} \mathrm{mol}^{-1}

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