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NCERT Class XII Chemistry
Chapter - Chemical Kinetics
Questions with Solutions

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Question : 24 of 39
Marks: +1, -0
Consider a certain reaction A → Products with k=2.0×102s1k = 2.0 \times 10^{-2} \mathrm{s}^{-1}. Calculate the concentration of A remaining after 100 s if the initial concentration of A is 1.0 mol L1^{-1}.
Solution:  
The units of k show that the reaction is of first order.
Hence, k=2.303tlog[R0][R]k = \frac{2.303}{t} \log \frac{[R_0]}{[R]}
or, 2.0×102=2.303100log1.0[R]2.0 \times 10^{-2} = \frac{2.303}{100} \log \frac{1.0}{[R]}
or, log[R]=0.8684\log [R] = -0.8684
[R]=\Rightarrow [R] = Antilog (0.8684)(-0.8684)
=0.1354molL1=0.1354 \mathrm{mol} \mathrm{L}^{-1}
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