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NCERT Class XII Chemistry
Chapter - Alcohols, Phenols and Ethers
Questions with Solutions

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Question : 30 of 45
Marks: +1, -0
Write the mechanism of the reaction of HI with methoxymethane.
Solution:  
The reaction between methoxymethane and HI is :
CH3−O−CH3+HI→CH3I+CH3OH\mathrm{CH_3-O-CH_3} + \mathrm{HI} \rightarrow \mathrm{CH_3I} + \mathrm{CH_3OH}
Step I : Generation of oxonium ion : Protonation of ether molecule
Step II : Nucleophilic attack on oxonium ion :
If excess HI is used, methanol formed above reacts with HI to form methyl iodide.
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