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NCERT Class XII Chapter
NCERT Class XII Chapter
Nuclei
Questions With Solutions
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Question : 27 of 31
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Consider the fission of by fast neutrons. In one fission event, no neutrons are emitted and the final end products, after the beta decay of the primary fragments are and . Calculate Q for this fission process. The relevant atomic and particle masses are: m = 238.05079 u, m = 139.90543 u , m = 98.90594 u
Solution:
The fission of U-238 by fast neutrons into fragments Ce-140 and Ru- 99 with energy released Q, The Q value, Q = [m (U-238) + – m (Ce-140) – m (Ru-99) Q = [238.05079 + 1.00867 – 139.90543 – 98.90594] amu × Q = 0.24809 × 931.5 MeV = 231.09 MeV = 231.1 MeV.
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