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NCERT Class XII Chapter
Moving Charges and Magnetism
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Question : 8 of 28
Marks: +1, -0
A closely wound solenoid 80 cm long has 5 layers of windings of 400 turns each. The diameter of the solenoid is 1.8 cm. If the current carried is 8.0 A, estimate the magnitude of B inside the solenoid near its centre.
Solution:  
Total number of turns in 80 cm length of solenoid can be calculated N = 5 × 400 = 2000 turns.
n = number of turnlength\frac{\text{number of turn}}{\text{length}} = 200080×10−2\frac{2000}{80 \times 10^{-2}} = 2500 turns/ m
Magnetic field near centre of long solenoid, B = μ0nI\mu_0 n I
B = 4π × 10−710^{-7} × 2500 × 8 or B = 8π × 10−310^{-3} T
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