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NCERT Class XII Chapter
Electrostatic Potential and Capacitance
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Question : 4 of 37
Marks: +1, -0
A spherical conductor of radius 12 cm has a charge of 1.6 × 10710^{-7} C distributed uniformly on its surface. What is the electric field
(a) inside the sphere
(b) just outside the sphere
(c) at a point 18 cm from the centre of the sphere?
Solution:  
R = 12 cm, q = 1.6 × 10710^{-7} C
(a) EinE_{in} = 0
(b) EoutE_{out} = 14πε0qr2\frac{1}{4\pi\varepsilon_0} \frac{q}{r^2} = 9 × 10910^9 × 1.6×107(12×102)2\frac{1.6 \times 10^{-7}}{(12 \times 10^{-2})^2} or EoutE_{out} = 1.0 × 10510^5 N C1C^{-1}
(c) EonE_{on} = 14πε0qR2\frac{1}{4\pi\varepsilon_0} \frac{q}{R^2} = 9 × 10910^9 × 1.6×107(12×102)2\frac{1.6 \times 10^{-7}}{(12 \times 10^{-2})^2} or EonE_{on} = 4.4 × 141^4 N C1C^{-1}
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