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NCERT Class XII Chapter
Electrostatic Potential and Capacitance
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Question : 24 of 37
Marks: +1, -0
What is the area of the plates of a 2 F parallel plate capacitor, given that the separation between the plates is 0.5 cm?
Solution:  
C = ε0Ad\frac{\varepsilon_0 A}{d} or A = C.dε0\frac{C.d}{\varepsilon_0} = 2×0.5×10−28.85×10−12\frac{2\times 0.5\times 10^{-2}}{8.85\times 10^{-12}}
orA = 1.13 × 109 m210^9\,\text{m}^2 = 1130 km2\text{km}^2
This is why ordinary capacitors are in the range of µF or less.
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