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NCERT Class XII Chapter
Electric Charges and Fields
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Question : 22 of 34
Marks: +1, -0
A uniformly charged conducting sphere of 2.4 m diameter has a surface charge density of 80.0 μC m−2m^{-2}.
(a) Find the charge on the sphere.
(b) What is the total electric flux leaving the surface of the sphere?
Solution:  
R = 2.4m2\frac{2.4m}{2} = 1.2 m , σ = 80.0 µ C m−2m^{-2} = 80 × 10−610^{-6} C m−2m^{-2}
(a) As σ = q4πR2\frac{q}{4\pi R^2}
So, q = 4πR24\pi R^2 × σ = 4 × 3.14 × (1.2)2(1.2)^2 × 80 × 10−610^{-6} or q = 1.45 × 10−310^{-3} C
(b) ϕ = qε0\frac{q}{\varepsilon_0} = 1.45×10−38.85×10−12\frac{1.45 \times 10^{-3}}{8.85 \times 10^{-12}} = 1.64 × 10810^8 N m2C−1m^2 C^{-1}
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