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NCERT Class XII Chapter
Dual Nature of Radiation and Matter
Questions With Solutions

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Question : 12
Total: 37
Calculate the
(a) momentum, and
(b) de Broglie wavelength of the electrons accelerated through a potential difference of 56 V.
Solution:  
An electron which is accelerated through a potential difference of 56 V will have kinetic energy K = 56 eV
(a) Momentum associated with accelerated electron
P = √2Km =
√2×56×1.6×10−19×9.1×10−31
= 4.04 × 10−24 Kg m s−1
(b) Wavelength of electron accelerated
λ =
h
p
 =
6.63×10−34
4.04×10−24
 = 0.164 nm
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